Battery Replacement: 2013 Infiniti JX35 3.5L V6

A charge and a half-infinite wire A half-infinite wire carries current I from negative infinity to the origin, where it builds up at a point charge with increasing q (so d q / d t=I ). Consider the circle shown in Fig. 9.12, which has radius b and subtends an angle 2 θwith respect to the charge. Calculate the integral ∫𝐁 ·d 𝐬 around this circle. Do this in three ways. (a) Find the B field at a given point on the circle by using the BiotSavart law to add up the contributions from the different