Gauss-Seidel Method - SlideServe

Apply Jacobi's method to the given system. Take the zero vector as the initial approximation and work with four-significant-digit accuracy until two successive iterates agree within 0.001 in each variable. In each case, compare your answer with the exact solution found using any direct method you like. 3 x1 x2 =1 x1 4 x2 x3 =1 x2 3 x3 =1 | Numerade

what is the main difference between jacobis and gauss seidal a convergence in jacobis method is faster b computations in jacobis can be done in parallel but not in gauss seidal c gauss seida 81542